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11 May 2015, 07:27
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D
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Difficulty:
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Question Stats:
88% (01:17) correct
12%
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wrong
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A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91
A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91
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22 Oct 2023, 01:52
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Official Solution:
A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91
According to the stem, the ball can be white, green, or yellow, so the probability is \(\frac{white + green + yellow}{total} = \frac{22 + 18 + 11}{60} = \frac{51}{60} = 0.85\).
Answer: D
A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91
According to the stem, the ball can be white, green, or yellow, so the probability is \(\frac{white + green + yellow}{total} = \frac{22 + 18 + 11}{60} = \frac{51}{60} = 0.85\).
Answer: D
General Discussion
11 May 2015, 07:45
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Total number of favourable balls = Total - (no of red + no of purple) = 60-(5+4) = 51.
Therefore: P(neither red nor purple)= 51/60 = 0.85 D it is
Therefore: P(neither red nor purple)= 51/60 = 0.85 D it is
