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A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,

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A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 11 May 2015, 07:27
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A
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D
E

Difficulty:

  5% (low)

Question Stats:

90% (01:34) correct 10% (02:23) wrong based on 68 sessions

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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 11 May 2015, 07:45
1
Total number of favourable balls = Total - (no of red + no of purple) = 60-(5+4) = 51.
Therefore: P(neither red nor purple)= 51/60 = 0.85 D it is
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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 11 May 2015, 08:03
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IMO D

Favorable/ Total ; 51/60 = 0.85
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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 11 May 2015, 21:30
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There are 9 red or purple balls, so 51 non-red, non-purple balls. So the answer is 51/60 -> (divide each side by 3) 17/20 or 85/100 (multiply each side by 5), D
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A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 11 May 2015, 22:01
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Bunuel wrote:
A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?

A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91

Kudos for a correct solution.


Ans: D

Solution: Find the probability of ball being either Red or Purple= (5/50)+(4/60)=9/60
probability of ball being neither Red nor Purple= 1-(9/60)= 51/60=0.85

So 0.85 is the answer
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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 18 May 2015, 05:18
Bunuel wrote:
A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?

A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91

Kudos for a correct solution.


OFFICIAL SOLUTION:

According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (22 + 18 + 11)/60 = 51/60 = 0.85.

Answer: D.
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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,  [#permalink]

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New post 04 Aug 2019, 11:40
1
Bunuel wrote:
A certain bag contains 60 balls — 22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?

A. 0.09
B. 0.15
C. 0.54
D. 0.85
E. 0.91

Kudos for a correct solution.



Since 60 - 5 - 4 = 51 balls are neither red nor purple, the probability that the ball will be neither red nor purple is 51/60 = 17/20 = 85/100 = 0.85.

Answer: D
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Re: A certain bag contains 60 balls —22 white, 18 green, 11 yellow, 5 red,   [#permalink] 04 Aug 2019, 11:40
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