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An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?
3/10 remains. So 6 minutes/(7/10) = x minutes/ (3/10). Solving for x yields 18/7.

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5
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It will be more than 2 and less than 3...It can only be D.
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Rate =7/10 *C/6= 7/60 *C
So for full capacity time taken =60/7
Extra time taken to fill the capacity = time for full tank -time for 7/10 capacity = 60/7-6 =18/7


Hence answer is D
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70% in 6 minutes, so 30% in 3*6/7 = 18/7 mins.
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suppose , capacity = 70 .
So to fill 7/10 of 70 i.e. 49 , it took 6 mints .
Hence to fill 70 it will take = 10*6/7 = 60/7 mints
So additional time = 60/7 - 6 = 18/7
Answer = d
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Bunuel
An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5

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1 litre in 6/7 min
7 litre in 6/7 ×7 = 6 min
Remaining 3 litres in 6/7× 3 = 18/7 min

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Bunuel
An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?

A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5

We can create the proportion:

6/(7/10) = n/(3/10)

60/7 = 10n/3

180 = 70n

180/70 = n

18/7 = n

Answer: D
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