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Bunuel

ABCD is a quadrilateral, with AB parallel to CD (see figure). E is a point between C and D such that AE represents the height of ABCD, and E is the midpoint of CD. If AB is 4 inches long, AE is 5 inches long, and the area of triangle AED is 12.5 square inches, what is the area of ABCD? (Note: figure not drawn to scale.)

A. 30 inches
B. 35 inches
C. 40 inches
D. 45 inches
E. 50 inches

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Attachment:
2015-07-01_1359.png

Solution -

Area of AED = 1/2(DE*AE) -> 12.5 = 0.5 (DE*5) -> DE = 5.
E is the mid point, so DE = EC =5.

Area of quadrilateral ABCD = 1/2(DC+AB)*AE = 0.5*(10+4)*5 = 35 inches^2.
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Bunuel

ABCD is a quadrilateral, with AB parallel to CD (see figure). E is a point between C and D such that AE represents the height of ABCD, and E is the midpoint of CD. If AB is 4 inches long, AE is 5 inches long, and the area of triangle AED is 12.5 square inches, what is the area of ABCD? (Note: figure not drawn to scale.)

A. 30 inches
B. 35 inches
C. 40 inches
D. 45 inches
E. 50 inches

Kudos for a correct solution.

Attachment:
2015-07-01_1359.png

MANHATTAN GMAT OFFICIAL SOLUTION:

If E is the midpoint of C, then CE = DE = x. You can determine the length of x by using what you know about the area of triangle AED:

A = (b*h)/2;
12.5 = 5x/2;
x = 5.

Therefore, the length of CD is 2x, or 10.

To find the area of the trapezoid, use the formula:
\(A=\frac{b_1+b_2}{2}*h=\frac{4+10}{2}*5=35\) in^2.

Answer: B.
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Hello,

I tried solving the problem in a slightly different way and ended up getting a different answer. There is obviously a gap in my understanding so would really appreciate if someone could point that out. Here was my thought process:

Since AB=4 and CE=AB, where is E is the midpoint of CD, wouldn't CD=2AB or 2CE or 2*4=8?

Area= (4+8)*5/2=30

Thanks again,
Asfand
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If we are not given that E is a midpoint, how can we solve this via decomposition?
I tried solving for the area of the triangle on the left, the rectangle in the middle but got stuck with the area of the triangle on the right.

How to solve for the area of the triangle on the right?
I have the height as 5 but not the base.

Thanks!
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