9^3(2^8 + 2^9/2) =

Question

9^{3}(\frac{2^{8} + 2^{9}}{2})=

(A)  2^{7}3^{6} 
(B)  2^{6}3^{7} 
(C)  6^{7} 
(D)  2^{8}3^{7} 
(E)  12^{4}

Kudos for a correct  solution .

KS15 · Answer

=9^3*2^8(2+1)/2
=3^2*3*2^8(3)/2
=3^6*2^7*3
=(3*2)^7
Answer C

AbdurRakib · Answer

9^3( \frac{(2^8+2^9)}{2} )
=9^3(2^-1)(2^8+2^9)
=9^3 * 2^7+9^3 * 2^8
=9^3*2^7(1+2)
=3^6*2^7(3)
=3^7 * 2^7
=(3*2)^7
=6^7

So,the  Correct Answer is C

noTh1ng · Answer

9^3*\frac{2^8+2^9}{2} 
 (3^2)^3*\frac{2^8*(1+2)}{2} 
 3^6*\frac{(3*2^8)}{2} 
 3^6*3*2^7 
 3^7*2^7 
 6^7

kunal555 · Answer

9^{3}(\frac{2^{8} + 2^{9}}{2})

=  3^{6}2^8(\frac{1+2}{2})

=  3^{6}2^8(\frac{3}{2})

=  3^7 2^7

=  6^7

Answer:- C

Bunuel · Answer

VERITAS PREP OFFICIAL SOLUTION:

When working with exponents, you should try to find common (typically prime) bases and multiply. First to multiply, you can factor a 2^8 out of each additive term within the parentheses to get:  9^{3} 2^{8} (\frac{(1+2)}{2}) . Then, perform the addition within the parentheses to get:  9^{3}2^{8} (\frac{3}{2}) .

You can break down  9^{3}  to be  (3^{2})^3 , which is  3^{6} , and then you have common prime terms for each exponent:  3^{6}2^{8} (\frac{3}{2}) .

Multiplying out the equation  3^{6}2^{8} (\frac{3}{2}) , you get:  3^7*3=3^8  and  \frac{2^{8}}{2} =2^7 , which can be simplified to  3^7*2^7 .

This can be expressed as  (3*2)^{7} = 6^{7} , and  the correct answer is C .

ydmuley · Answer

9^{3}(\frac{2^{8} + 2^{9}}{2})=

= 9^{3}(2^{7} + 2^{8})

= 9^{3} * 2^7 (2 + 1)

= 9^{3} * 2^7 * 3

= 3^{6} * 2^7 * 3

= 3^{7} * 2^7

= 6^{7}

Hence, Answer is C

JeffTargetTestPrep · Answer

We can re-express 9^3 as (3^2)^3, or 3^6, and we can re-express the fraction (2^8 + 2^9)/2 as two separate fractions. Thus, we have:

3^6

3^6(2^7 + 2^8)

3^6

3^7 x 2^7 = 6^7

Answer: C

Abhishek009 · Answer

3^{6}(\frac{2^{8}(1 + 2)}{2})

Or,  3^{6}*2^{7}*3

Or,  6^7 , ANswer must be (C)

omavsp · Answer

9^3*((2^8+2^9)/2)=
3^6*(2^7+2^8)=
3^6*2^7*(1+2)=
3^6*2^7*3=
3^7*2^7=
6^7

bumpbot · Answer

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9^3(2^8 + 2^9/2) =

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