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Thank you, guys! You've done an awesome job!
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Thank you, guys! You've done an awesome job!

hi, do you have more similar questions like this? I really like the such kind of question.
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TeymurHajiyev
Thank you, guys! You've done an awesome job!

hi, do you have more similar questions like this? I really like the such kind of question.


Hope it helps.
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TeymurHajiyev
Students in certain group know either English or French or both. If 30% of those who know English know French, and 60% of those who know French do not know English, which of the following could be the number of students in the group?

A) 12

B) 17

C) 23

D) 29

E) 31

Students know either English or French or both

30% of those who know English know French
60% of those who know French do not know English -> 40% of those who know French know English.

Let the no. of people who know English be x. So the people who knows both = 0.3x
and the number of people who know french be y. So the people who knows both = 0.4y

0.3x = 0.4y
x = 4y/3

Total number of people = x + y - 0.4y = 4y/3 + y -4/10 y = 7y/3 - 2/5y = 29y/15.

So total number of people must be a multiple of 29

Answer D
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TeymurHajiyev
Students in certain group know either English or French or both. If 30% of those who know English know French, and 60% of those who know French do not know English, which of the following could be the number of students in the group?

A) 12

B) 17

C) 23

D) 29

E) 31


Let the number of students who know English be E

Let the number of students who know French be F

Let the total be "T"

We get two equations from the information:-

1) 0.7E + F = T
2) E + 0.6F = T

Therefore 4F = 3E or F = 3E/4

Substituting the value of F in one of the equations we get:-

T = 29E/20

Therefore, if E = 20 then T = 29

None of the other options are valid as T has to be a whole number.

Option D is the correct answer.
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