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Updated on: 30 Jan 2016, 07:21
Originally posted by MathRevolution on 27 Jan 2016, 18:24.
Last edited by chetan2u on 30 Jan 2016, 07:21, edited 3 times in total.
Last edited by chetan2u on 30 Jan 2016, 07:21, edited 3 times in total.
Reformatted the question.
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C
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Which of the following is satisfied with |x-4|+|x-3|<2?
A. 1<x<5
B. 2<x<5
C. 2.5<x<4.5
D. 2.5<x<4
E. 3<x<4
A. 1<x<5
B. 2<x<5
C. 2.5<x<4.5
D. 2.5<x<4
E. 3<x<4
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27 Jan 2016, 18:55
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If we put x=2.51 , 2.501 ...
|x-4|+|x-3| = 1.98 , 1.998 ..... just below 2
Again if we put x= 4.49,4.499.....
|x-4|+|x-3|=1.98,1.998 ... just below 2
So Range should be
2.5<x<4.5
Answer (C)
|x-4|+|x-3| = 1.98 , 1.998 ..... just below 2
Again if we put x= 4.49,4.499.....
|x-4|+|x-3|=1.98,1.998 ... just below 2
So Range should be
2.5<x<4.5
Answer (C)
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27 Jan 2016, 19:01
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MathRevolution
Remember that |x-a| represents distance of x from 'a'. As mentioned in the question,
|x-4|+|x-3|<2 simply means that you need to find the range of 'x' such that distance of x from 4 + distance of x from 3 < 2.
Refer to the attached image, you realize that the distance 'y' when it is in between 3 and 4 will always be <2. For regions x<3 or x>4, the sum of the distances of 'y' from 3 and 4 will be <2 only when
y+1+y<2 ---> 2y+1<2 ---> y<0.5 or in other words, range of x is ---> 2.5 < x < 4.5
Attachment:
2016-01-27_20-50-35.jpg [ 6.25 KiB | Viewed 14265 times ]
C is thus the correct answer.
Alternate solution: using POE to arrive at the correct answer.
Once you know that the sum of the distances of x from 3 and 4 must be < 2,
A. 1<x<5 . Try with x=1.5. Clearly the distance of 1.5 from 3 and 4 will be >2. Eliminate.
B. 2<x<5 . Take x=2.1. Again, the distances of 2.1 from 3 and 4 (=0.9 and 1.9 respectively) will sum to > 2. Hence Eliminate.
C. 2.5<x<4.5. Works for all possible values. Keep.
D. 2.5<x<4. Take x=4.2. The distances of 4.2 from 3 and 4 (=1.2 and 0.2 respectively) will sum to < 2 but this value is NOT in the given range, thus incomplete range. Hence Eliminate.
E. 3<x<4. Take x=2.6. It works for the given sums of the distances < 2 but is not in the given range, thus incomplete range. Hence eliminate.
C is thus the correct answer.
Hope this helps.
