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Median of a series with odd number of elements is its middle value (when the series is arranged order. So in this case, since we have 5 elements, the median will be the 3rd element.
Thanks to the three 3's in the series, whatever value m takes, the 3rd element will always be 3.
Hence, our Median = 3

Now, Range = Median = 3 (given)

m can take 3 places-
Case 1: 1, 3, 3, 3, m Range: \(m-1=3 => m=4\) (not an option)
Case 2: 1, m, 3, 3, 3 Range: \(3-1\neq{3}\)
Case 3: m, 1, 3, 3, 3 Range: \(3-m=3 => m=0\)

Ans: B
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If the median and the range of 1, 3, 3, 3, m are the same, which of the following can be the value of m?

A. -1
B. 0
C. 1
D. 2
E. 3

==> range=Max-min and median is 3. m=4,0 is possible from 3=4-1=3-0.
However, there is only 0 and the answer is B.
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MathRevolution
If the median and the range of 1, 3, 3, 3, m are the same, which of the following can be the value of m?
A. -1 B. 0 C. 1 D. 2 E. 3


Median of {1, 3, 3, 3, m } will be 3

Range is the Max - Min = 3 { According to the problem}

There are 2 possibilities m > 3 or m < 3

If m > 3 then it is the max value -

3 = m - 1 { Because Range = Max - Min }

So, m = 4 ; Not in given option

If m < 3

3 - m = 3

So, m = 0

So, answer is definitely B :-D :lol: :P

PS : This problem is actually very easy if U know what " Range " means
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If the median and the range of 1, 3, 3, 3, m are the same, which of the following can be the value of m?

set is {1, 3, 3, 3, m}
Median = 3
so,range = median = 3

m can take 3 places-
Case 1: {1, 3, 3, 3, m}
Range: m−1=3
or, m=4 (not in option)

Case 2: {1, m, 3, 3, 3}
Range: 3−1≠3 (rejected)

Case 3: {m, 1, 3, 3, 3}
Range: 3−m=3
or,m=0

correct answer B
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