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05 Jul 2016, 12:24
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (00:51) correct
10%
(01:17)
wrong
based on 117
sessions
History
Date
Time
Result
Not Attempted Yet
Danny can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Danny has in his herd?
A. 120
B. 155.
C. 180
D. 336.
E. 456
A. 120
B. 155.
C. 180
D. 336.
E. 456
FacelessMan
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Schools: Duke '19 Kenan-Flagler '19
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05 Jul 2016, 12:28
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Danny can divide his herd into 5 equal parts and also to 6 equal parts => No of cows = Multiple of 5 and 6 = Multiple of 30.
Only option A and C qualify.
Now 2nd condition : but not to 9 equal parts : So it should not be a multiple of 9. Only A.
Only option A and C qualify.
Now 2nd condition : but not to 9 equal parts : So it should not be a multiple of 9. Only A.
Nightfury14
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05 Jul 2016, 12:32
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Bunuel
Ans.
On first look B, D & E are not divisible either by 5 or 6 - ruled out.
A & C divisible by both 5 & 6, but 180 is divisible by 9.
Hence Ans is (A).
Bunuel - can we expect kudos for immediate replies + correct answers.
Good luck
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