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Bunuel
XYZ Corporation has a ratio of 1 : 6 female to male. If the average salary for the female employees is $217,800 and XYZ pays $2,395,800 in salary to female employees, how many men work at XYZ Corporation?

A. 77
B. 66
C. 55
D. 24
E. 11

Total salary to female employees is \(2395800\)
Salary of a female employees is \(217800\)

So, Total number of female employees is \(\frac{2395800}{217800} = 11\)

Thus, total number of male employees is 11*6 = 66

Answer will be (B) 66
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Bunuel
XYZ Corporation has a ratio of 1 : 6 female to male. If the average salary for the female employees is $217,800 and XYZ pays $2,395,800 in salary to female employees, how many men work at XYZ Corporation?

A. 77
B. 66
C. 55
D. 24
E. 11

We are given that female : male = x : 6x.

We are also told that the average salary for the female employees is $217,800 and XYZ pays $2,395,800 in salary to female employees. Thus, we have:

217,800x = 2,395,800

x = 11

Thus, we have 6x = 66 men at XYZ Corporation.

Answer: B
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You can deduce the answer without actually performing the calculation :
Since the ratio of F:M is 1:6
and the number of females can be deduced by divising the total of female salaries by the average female salary
The answer must be divisible by 6 (by 3 and 2)
From this, one can eleminate the answers A; C; E
Then just understand that males are 6 times the number of females and a quick glance at the operation allow to conclude that there is at least 10 female worker so answer D cannot be an option, Hence the only answer left is :B

No calculation at all

Hope that make sense,
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