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Bunuel
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8^(1/2)=4^x
2^(3/2) =2^(2x)
3/2 = 2x
x= 3/4

Bunuel, did I make a mistake or are the answers incorrect?
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mynamegoeson
Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/2

B. 1

C. 2

D. 3

E. 4

\(8^(1/2)\) = 2.83

Putting values of x in 4^x

if x=1/2, 4^x = 2
If x=1, 4^x=4
if x=2, 4^x = 16

Closest value is 2 hence A

Please correct me if i am wrong


Let me correct myself

\(8^{(\frac{1}{2})} = 4^x\)
We can write it as
64^(1/4) = 64^(x/3)

x/3 = 1/4
x=3/4
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Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/2

B. 1

C. 2

D. 3

E. 4

Bunuel why so many questions posted today has wrong options.. This question also has none of the options matching with the correct answer..

Please check the options again.
As for the solution .. \(8^{(\frac{1}{2})} = 4^x\)
-> 2^(3/2) = 2 ^(2x)
-> 3/2 = 2x
-> x = 3/4

No options is matching the answer...
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sashiim20
Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/2

B. 1

C. 2

D. 3

E. 4

\(8^{(\frac{1}{2})} = 4^x\)

\(\sqrt{2^3} = (2*2)^x\)

\(2\sqrt{2} = (2*2)^x\)

Cancelling 2 from both sides we get;

\(\sqrt{2} = (2)^x\)

\(2^{(\frac{1}{2})} = 2^x\)

\(x = \frac{1}{2}\) . Answer (A) ...

How did you cancelled 2 from both sides ??. We can't cancel 2 like this
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Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/4

B. 2/3

C. 3/4

D. 4/3

E. 1

Given: \(8^{(\frac{1}{2})} = 4^x\)

Rewrite 8 as 2³ and 4 as 2² to get: (2³)^(1/2) = (2²)^x
Apply power of a power law to both sides: 2^(3/2) = 2^(2x)
So, we can conclude that 3/2 = 2x
Divide both sides by 2 to get: 3/4 = x

Answer: C

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mynamegoeson
Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/2

B. 1

C. 2

D. 3

E. 4

\(8^(1/2)\) = 2.83

Putting values of x in 4^x

if x=1/2, 4^x = 2
If x=1, 4^x=4
if x=2, 4^x = 16

Closest value is 2 hence A

Please correct me if i am wrong

I don't think we can work with closest value.. No approximation is asked in question.
Also approximating 2.83 to 2 is not the right way of solving quantitative questions.. We must keep in mind that approximation should look like approximation.. I think here the options are wrong...
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mynamegoeson
mynamegoeson
Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/2

B. 1

C. 2

D. 3

E. 4

\(8^(1/2)\) = 2.83

Putting values of x in 4^x

if x=1/2, 4^x = 2
If x=1, 4^x=4
if x=2, 4^x = 16

Closest value is 2 hence A

Please correct me if i am wrong


Let me correct myself

\(8^{(\frac{1}{2})} = 4^x\)
We can write it as
64^(2/2) = 64^(x/3)

x/3 = 1
x=3
Hence option D

mynamegoeson
\(8^{(\frac{1}{2})}\) is not equal to 64^(2/2) . it is equal to 64^(1/4)
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Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/4

B. 2/3

C. 3/4

D. 4/3

E. 1

Apologise to all of you. Copied options of another question here. Edited.
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Bunuel
Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/4

B. 2/3

C. 3/4

D. 4/3

E. 1

Apologise to all of you. Copied options of another question here. Edited.

No issues Bunuel .. You are doing great work.. You have posted so many questions on daily basis. So sometimes you might get confused with options.. Humans :)
But your work is helping us a lot in preparation of Quant. Keep up the good work..
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If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?


Since \(8^{(\frac{1}{2})} = 2*\sqrt{2}\)

We have to find which value of x makes \(4^x = 2*\sqrt{2}\)

Of the available options, \(x=\frac{3}{4}\)(Option C) makes

\(4^x = 4^{\frac{3}{4}} = (4*4*4)^{\frac{1}{4}} = 2*\sqrt{2} = 8^{(\frac{1}{2})}\)
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\(8^{\frac{1}{2}} = 4^{x}\)

\(2^{\frac{3}{2}} = 2^{2x}\)

\(2x = \frac{3}{2}\)

\(x = \frac{3}{4}\). Ans - C.
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Bunuel
If \(8^{(\frac{1}{2})} = 4^x\), what is the value of x?

A. 1/4

B. 2/3

C. 3/4

D. 4/3

E. 1

Lets simplify the given equation and determine x:

8^(½) = 4^x

(2^3)^½ = 2^2x

2^3/2 = 2^2x

3/2 = 2x

x = 3/4

Answer: C
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Step 1: Simplify left-hand side
81/2=8=4⋅2=228^{1/2} = \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2}81/2=8=4⋅2=22
[hr]
Step 2: Express both sides in base 2
81/2=(23)1/2=23/28^{1/2} = (2^3)^{1/2} = 2^{3/2}81/2=(23)1/2=23/2 4x=(22)x=22x4^x = (2^2)^x = 2^{2x}4x=(22)x=22x
[hr]
Step 3: Equating exponents (same base)
23/2=22x2^{3/2} = 2^{2x}23/2=22x 32=2x\frac{3}{2} = 2x23=2x x=34x = \frac{3}{4}x=43
[hr]
Answer: C. 3/4

Luckisnoexcuse


\(8^(1/2)\) = 2.83

Putting values of x in 4^x

if x=1/2, 4^x = 2
If x=1, 4^x=4
if x=2, 4^x = 16

Closest value is 2 hence A

Please correct me if i am wrong
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