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Bunuel
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There are two possibilities for the values, one is negative and the other is positive(as a≠0)
Let assume this value to be +1/2 and -1/2

A. \(a>a^2\)
Though it works for the positive value(+1/2) it doesn't work for the negative value
B. \(a<a^2\)
Though it works for the negative value(-1/2) it doesn't work for the positive value
C. \(a^2>a^3\)
This works for both the positive value(+1/2) and the negative value(-1/2)

Hence, Option C is the correct answer.
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Option 1--> 0<a<1 does not cover full range
option 2--< a>1 or a<0 does not cover range
option 3--> a<1 covers full range , hence true for all values of a

Ans:C
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