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ydmuley
What is the product of integers a, b, and c if \(2^{a} * 3^{b} * 5^{c} = 270,000,000\)

A. 141

B. 147

C. 162

D. 235

E. 270

Responding to a pm:

Note that cyclicity has no role to play in this. For it to work in a question, we need to know the power of the term. Here there are too many variables. It is a simple question of prime factorisation.
This is the reason GMAT is tricky - it's not the concept per say which is hard to understand, it's more about WHICH concept will help solve the problem.
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ydmuley
What is the product of integers a, b, and c if \(2^{a} * 3^{b} * 5^{c} = 270,000,000\)

A. 141

B. 147

C. 162

D. 235

E. 270

Let’s break 270,000,000 into its prime factors.

270,000,000 = 27 x 10,000,000 = 3^3 x 10^7 = 2^7 x 3^3 x 5^7, so a x b x c = 7 x 3 x 7 = 147.

Answer: B
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