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Its 62, Option C.
Lower limit is 169 = 13^2, upper limit is 324 = 18^2.
So possible values between limits are 14,15,16,17 and sum of these is 62.
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Bunuel
If x is an integer, and 169 < x^2 < 324, which of the following is the sum of all possible values of x?


(A) 0

(B) 61

(C) 62

(D) 75

(E) 93

169 < x^2 < 324
=> 13^2 < x^2 < 18^2

X can take values 14, 15 , 16 , 17 and - 14 , -15 , -16 , -17
Sum = 0

Answer A
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Bunuel
If x is an integer, and 169 < x^2 < 324, which of the following is the sum of all possible values of x?


(A) 0

(B) 61

(C) 62

(D) 75

(E) 93


Hi...
since x is an integer and it has an EVEN power, don't get into calculation ..
ans is 0, as every positive value of x will have a corresponding similar negative value. these will cancel out when added..

so finally ans will be ZERO..
A
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X can take 14,15,16,17 and -14,-15,-16,-17. So summation equals to zero.
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If x is an integer, and 169 < x^2 < 324, which of the following is the sum of all possible values of x?

This question is logical and answering it should not take more than 30 sec.
169 < x^2 < 324, means 13<X<18 or -18<X<-13

means X will take same positive and negative values . Hence addition of all values = 0
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Bunuel
If x is an integer, and 169 < x^2 < 324, which of the following is the sum of all possible values of x?


(A) 0

(B) 61

(C) 62

(D) 75

(E) 93

We are given that 169 < x^2 < 324. That is, 13 < |x| < 18. If x is positive, x = 14, 15, 16, 17. If x is negative, x = -14, -15, -16, -17. We see that for every positive value of x, the opposite (or negative) is also a possibility. Thus, the sum of all values of x will be zero.

Answer: A
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Okay.
The possible values of x =>
14,-14
15,-15
16,-16
17,-17


Hence sum => Zero.

The presence of zero in the options signifies that this is a Novel question...


Best
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nvnt
Its 62, Option C.
Lower limit is 169 = 13^2, upper limit is 324 = 18^2.
So possible values between limits are 14,15,16,17 and sum of these is 62.

X can also take a negative value since it is squared. So -14,14,-15,15,-16,16,-17,17, add all of them you get a 0.

Cheers,
PV66.

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