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aashishagarwal2
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aashishagarwal2
What is the value of \(2 + 2^1 + 2^2 + 2^3...........2^{18}\)?

A) \(2^{19}\)
B) \(2^{171}\)
C) \(2^{172}\)
D) \(2^{18!}\)
E) \(2 + 2^{18!}\)

pushpitkc's solution is the same as mine (look for a pattern).
However, we can also solve the question quickly by eliminating 4 of the answer choices.

Notice what would happen if we took the sum 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 replaced each value with 2^18
The NEW sum would definitely be bigger than the ORIGINAL sum

That is: 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 < 2^18 + 2^18 + 2^18 + 2^18 . . . + 2^18 + 2^18
Notice that the NEW sum is the sum of nineteen 2^18's
So, we can write: 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 < (19 )(2^18)
Now notice that 19 < 2^5, so we can write: 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 < (19 )(2^18) < (2^4 )(2^18)

Simplify the right-most expression to get: 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 < (19 )(2^18) < 2^22

So, we can conclude that: 2 + 2^1 + 2^2 + 2^3 + . . . . 2^17 + 2^18 < 2^22

Only answer choice A is less than 2^22

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Wow, this question made it confusing because of the additional 2^1. At first I did not realize there was an extra 2 in power of 1. Therefore, I couldnt' find my answer. Later on realizing that I confidently picked A = 2^19. Use the formula of the geometric progression and you should be fine.
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2^n = 2 + 2^1 + ... + 2^n-1

Works with every other number as well.

Solution A
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