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Updated on: 28 Oct 2017, 12:49
Originally posted by MathRevolution on 12 Oct 2017, 01:49.
Last edited by MathRevolution on 28 Oct 2017, 12:49, edited 1 time in total.
Last edited by MathRevolution on 28 Oct 2017, 12:49, edited 1 time in total.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
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Question Stats:
53% (02:09) correct
47%
(02:18)
wrong
based on 191
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A={x| x^2>9}, B={x| 1<x^2<16}, C={x| x^2<25}, what is the range of A∩B∩C?
A. |x|<4
B. 3<|x|<5
C. |x|<5
D. 1<|x|<4
E. 3<|x|<4
A. |x|<4
B. 3<|x|<5
C. |x|<5
D. 1<|x|<4
E. 3<|x|<4
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12 Oct 2017, 02:54
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A={x| x^2>9} - This set contains all positive numbers greater than x=3
B={x| 1<x<16} - This set contains all positive number from x=1.1 to x=15.9
C={x| x^2<25} - This set contains all positive numbers from x=-4.9 to x=4.9
If we have been asked to find the intersection of the three sets,
we need to find the common numbers which is 3<|x|<5(Option B)
P.S if x is an integer, then Option E is the correct answer.
B={x| 1<x<16} - This set contains all positive number from x=1.1 to x=15.9
C={x| x^2<25} - This set contains all positive numbers from x=-4.9 to x=4.9
If we have been asked to find the intersection of the three sets,
we need to find the common numbers which is 3<|x|<5(Option B)
P.S if x is an integer, then Option E is the correct answer.
16 Oct 2017, 07:14
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A={x| x^2>9} = {x| |x|^2>9} = {x| |x|>3}.
B={x| 1<x^2<16}={x| 1<|x|^2<16}={x| 1<|x|<4},
C={x| x^2<25}={x| |x|^2<25}={x| |x|<5}.
A∩B∩C = { x | 3 < |x| < 4 }.
Therefore, the answer is E.
B={x| 1<x^2<16}={x| 1<|x|^2<16}={x| 1<|x|<4},
C={x| x^2<25}={x| |x|^2<25}={x| |x|<5}.
A∩B∩C = { x | 3 < |x| < 4 }.
Therefore, the answer is E.
