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Bunuel
If the radius of a circle is decreased by 10%, by what percent is its area decreased?

(A) 10

(B) 19

(C) 21

(D) 79

(E) 81
Scale factor:
All changes in dimension of a figure have to do with length. Length is increased or decreased by a scale factor, \(k\)

Decrease in one length only (one dimension) = multiply by \(k\)

Decrease in area?
Area = length*length (two dimensions)
Multiply by \((k*k)= k^2\)

Original area = A
New area = (original area)*(\(k^2\))
(.9)*(.9)*(A) = .81A

Percent decrease: \(\frac{New-Old}{Old}*100\)

\((\frac{-.81A-A}{A}*100) =\frac{|-.19|}{1}*100= 19\)
% decrease

Answer B

* Decrease in volume, e.g. cube, if change is uniform = (length * length * length) = multiply by \((k*k*k) = k^3\)
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Bunuel
If the radius of a circle is decreased by 10%, by what percent is its area decreased?

(A) 10

(B) 19

(C) 21

(D) 79

(E) 81

Area = \pi r^2

Since r' = .9r
New Area = \(\pi r'^2 = \pi .81 r^2 = (1-.19)\pi r^2 \)

IMO B
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