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Lets first calculate the radius of the circle
Given, area of circle = 18π
so: π∗R*R=18π∗R*R=18π
R*R=18,
R=3√2

Hence the diameter= 6√2
Side of a square inscribed in a circle is Diameter/√2

=> Side of square= 6√2/√2= 6

Thus answer is B
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I found it easiest to draw a circle with an inscribed and then create a right triangle with the two legs being equal to the radius and the hypotenuse being one of the sides of the inscribed square. Then we can solve for the hypotenuse by
a^2+b^2=c^2
c^2=36
c = 6

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Bunuel
A square is inscribed in a circle of area \(18\pi\). Find a side of a square.

A. 3
B. 6
C. \(3\sqrt{2}\)
D. \(3\sqrt{2}\)
E. Cannot be determined

Since the square is inscribed in the circle, the diagonal of the square is equal to the diameter of the circle.

Let’s determine the diameter of the circle:

πr^2 = 18π

r^2 = 18

r = √9 x √2

r = 3√2, so diameter = diagonal = 6√2

Since diagonal of a square = side√2, the side of the square is 6.

Answer: B
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