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uzouka123
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Substituting m=10 in equation
We get
n-1000=80

N=-920

n/m=-920/10= -92

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uzouka123
If \(\frac{(n+10^3)}{(m+10)}=4\) and m=10, then \(\frac{n}{m}\)= ?

(A) -92
(B) 4-10^-2
(C) 4x10^2
(D) 4
(E) 99



\(\frac{(n+10^3)}{(m+10)}=4\)

Or, \(n + 1000 = 4(10 + 10)\)

Or, \(n + 1000 = 80\)

So, \(n = -920\)

Now, \(\frac{n}{m}\)= \(\frac{-920}{10}\) = \(-92\) , Answer must be (A)
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\(\frac{(n+10^3)}{(m+10)}=4\)
\(\frac{(n+10^3)}{(10+10)}=4\)
\(\frac{(n+10^3)}{20}=4\)

\(n+10^3=80\)

\(n=80-1000=-920\)

\(\frac{n}{m}= \frac{-920}{10}\)

\(\frac{n}{m}= -92\)
uzouka123
If \(\frac{(n+10^3)}{(m+10)}=4\) and m=10, then \(\frac{n}{m}\)= ?

(A) -92
(B) 4-10^-2
(C) 4x10^2
(D) 4
(E) 99


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