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Kimberly77
BrentGMATPrepNow
Which of the following is closest to \(\frac{(\sqrt{150})(\sqrt{405})}{\sqrt{105}-\sqrt{50}}\)?

A) 10
B) 20
C) 40
D) 80
E) 120

Hi BrentGMATPrepNow, I approximate it as \(\frac{(\sqrt{100 + 50})(\sqrt{400 + 5})}{\sqrt{100 + 5}-\sqrt{50}}\)
So I get (10 + 7) (20 * square_root 5 / 10 * square_root 5 - 7
17 * 20 * square_root 5 / 10 square_root 5 - 7 and get answer 113.3
What went wrong here? Could you advise? Thanks Brent

Hi Kimberly,

You are using a square root property that doesn't exist.
That is, there's no square root property that says \(\sqrt{x+y} = \sqrt{x} + \sqrt{y}\)

Tip: If you're not entirely sure whether a property is true, you can always test numbers.
For example \(\sqrt{4}\) can be written as \(\sqrt{1+1+1+1}\)
If we apply your faulty property we get, \(\sqrt{1+1+1+1} = \sqrt{1} + \sqrt{1} + \sqrt{1} + \sqrt{1} = 1+1+1+1 = 4\)
So, by applying your property we get \(\sqrt{4} = 4\), which is not true, which means the property can't be true.
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Great explanation always and crystal clear now thanks BrentGMATPrepNow
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rt(150)=12.7, rt(405)=20
rt(105)=10, rt(50)=7

12.5 x 20/3
=12.5x6=75 (approx)

80)
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Can someone solve this without approximation I'm dtuck
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kayarat600

BrentGMATPrepNow
Which of the following is closest to \(\frac{(\sqrt{150})(\sqrt{405})}{\sqrt{105}-\sqrt{50}}\)?

A) 10
B) 20
C) 40
D) 80
E) 120

Can someone solve this without approximation I'm dtuck

The expression results in an irrational number, so you’ll have to approximate at some point - there’s no way to get an exact integer value without estimation.
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