Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
04 May 2019, 02:46
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
11% (04:16) correct
89%
(03:27)
wrong
based on 18
sessions
History
Date
Time
Result
Not Attempted Yet
AB, CD and EF are three parallel lines, in that order. Let d1 end d2 be the distances from CD to AB and EF respectively. d1 and d2 are integers, where d1:d2 = 2:1, P is a point on AB, Q and S are points on CD and R is a point on EF, If the area of the quadrilateral PQRS is 30 square units, what is the value of QR when value of SR is the least?
A. slightly less than 10 units
B. 10 units
C. slightly greater than 10 units
D. slightly less than 20 units
E. slightly greater than 20 units
A. slightly less than 10 units
B. 10 units
C. slightly greater than 10 units
D. slightly less than 20 units
E. slightly greater than 20 units
05 May 2019, 08:22
Kudos
Bookmarks
Manas1212
Look at the attached sketch
Least value of SR means it is the altitude between CD and EF, so d2..
Now d2 is an integer and obviously a positive one, so least value =1. Thus d1=2...
Area of parallelogram = A(PQS)+A(QSR)=\(\frac{1}{2}*QS*2+\frac{1}{2}*QS*1=\frac{3}{2}*QS=30....QS=20\)
Now QR is the hypotenuse of triangle PQS where QS =20 and SR =1..
so QR=\(\sqrt{20^2+1^2}=\sqrt{402}\)..Slightly more than \(\sqrt{400}\), that is slightly more than 20.
E
Attachments
1201.png [ 40.16 KiB | Viewed 3627 times ]
udaypratapsingh99
Joined: 12 Jan 2019
Last visit: 11 Nov 2025
Posts: 395
Given Kudos: 372
Location: India
Concentration: Strategy, Leadership
Schools: Fuqua '24 Harvard '24 LBS '24 NTU NUS Said '23 Ross '24 Sloan '24 Stanford '24 Tepper '24 Tuck '24 Wharton '24 Yale '24
GMAT 1: 660 Q47 V34
Products:
Schools: Fuqua '24 Harvard '24 LBS '24 NTU NUS Said '23 Ross '24 Sloan '24 Stanford '24 Tepper '24 Tuck '24 Wharton '24 Yale '24
GMAT 1: 660 Q47 V34
Posts: 395
06 May 2019, 04:37
Kudos
Bookmarks
Manas1212
d1:d2
QR =?
SR is least
If SR is least, it means SR =1. Let’s take QS =x. Also PQ =2.
Hence
[(1/2) * x * 2] + [(1/2) * x * 1] = 30
x = 20
So, QR = squareroot(20^2 + 1^2) = squareroot(401)
This value is slightly greater than 20 units.
Attachments
5b9b71df02f9890c839d62be1b1bb3a3_view.png [ 28.09 KiB | Viewed 3440 times ]
