If (a, b) represents all the points that passes through the line 6y -3

Question

If (a, b) represents all the points that pass through the line 6y -3x = 1, then how many integral values can the point (a, b) take?

A. 0
B. 1
C. 4
D. 5
E. More than 5

GMATinsight · Answer

6y -3x = 1
i.e. 3(2y - x) = 1

i.e. (2y - x) = 1/3

if x and y are integers then 2y-x also will be an integer and hence can NOT be 1/3  hence

There is no integer solution possible for the equation

Answer: Option A

Kinshook · Answer

Asked: If (a, b) represents all the points that pass through the line 6y -3x = 1, then how many integral values can the point (a, b) take?
6b - 3a = 1
3(2b-a) = 1
No values of (a, b) will satisfy the equations since LHS is a multiple of 3 while RHS is not.

IMO A

firas92 · Answer

6y -3x = 1

x=\frac{6y-1}{3}

Since y is an integer, 6y is a multiple of 3 and so 6y-1 is never a multiple of 3

So there are no integer solutions

Answer is A

Posted from my mobile device

bumpbot · Answer

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If (a, b) represents all the points that passes through the line 6y -3

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If (a, b) represents all the points that passes through the line 6y -3

Prep Toolkit

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