If q, r, and s represent three numbers in which r = q + 8 and s = r +

Question

If q, r, and s represent three numbers in which r = q + 8 and s = r + 11, what is the result when the median of the three numbers is subtracted from their mean?

A. -1
B. 0
C. 1
D. 2
E. 3

nkme2007 · Answer

Sequence becomes q, q+8 and q+19.

Median : q+8
Mean : q+9

Difference : 1

GMATinsight · Answer

Three numbers are 
q
r = q+8
s = r+11 = q+8 + 11 = q+19

i.e.  Median = r = (q+8)

Mean = \frac{q+(q+8)+(q+19)}{3} = q+9

Mean - Median = (q+9) - (q+8) = 1

Answer: Option C

Manasvi1 · Answer

No.s are q,r,s
Given,
 r = q + 8 &
 s = r + 11
=> s = q + 8 + 11 = q + 19

Now, no.s are q , q + 8 , q + 19
Therefore,
 Median  = q + 8 &
 Mean  =  \frac{q + q + 8 + q + 19}{3}  =  \frac{3q + 27}{3}  = q + 9

So, Difference between mean and median = (q + 9) - (q + 8) = q + 9 - q - 8 = 1

Hence, OA is (C)

yashikaaggarwal · Answer

Three numbers q,r and s
where, r = q + 8 => r-8 = q and s = r + 11
can be written as r-8,r,r+11
in which median = r
mean = Total/no.of units
mean = r-8+r+r+11/3
mean = 3r +3/3
mean = r+1

subtracting median from mean = r+1-r = 1
answer is C

Kinshook · Answer

Asked: If q, r, and s represent three numbers in which r = q + 8 and s = r + 11, what is the result when the median of the three numbers is subtracted from their mean?

r = q + 8 
s = r + 11 = q + 19

Set = {q, q+8, q+19}
Median = q + 8

Mean = (q + q + 8 + q + 19)/3 = (3q + 27)/3 = q + 9

Mean - Median = (q + 9) - (q + 8) = 1

IMO C

RaghavKhanna · Answer

r = q + 8
s = r + 11

=>  s > r > q

Mean = (r + s + q)/3 = r+1

Median = r

=> Mean - Median = r + 1 - r = 1

Answer: C

daniformic · Answer

r=q+8
s=r+11
q=r-8

If R=11
Mean=12
Median=11

Mean (12) - Median (11) = 1

Answer -> C

ThatDudeKnows · Answer

Let’s just Plug In. Make q=0. That means r=8 and s=19. Median = 8. Mean = 27/3 = 9. Mean - median = 9-8 = 1.

Answer choice C

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