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Bunuel,

I agree with above posters that \(5^{2X}= 676\) I'm wondering what will be value of X if \(5^x=26\)
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Bunuel,

I agree with above posters that \(5^{2X}= 676\) I'm wondering what will be value of X if \(5^x=26\)

You don't need to find the value of x to answer the question. If still interesting x = log(26)/log(5) (x≈2.0244).
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While the above method i.e. \(26^2\) is easiest way to answer, logically we can also think of 26 as \((5^2+ 5^0)\).

while squaring i.e.\( (5^2+5^0)^2 \)we get \((a+b)^2=a^2+b^2+2ab\)

i.e. \((5^2)^2+(5^0)^2+2*5^2*5^0 =625+1+2*25=676\)
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5^x = 26
5^2x = (5^x)^2 = 26^2

26*26 =676
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1) If 5^x = 26, then x is pretty dang close to 2 since 5^2 = 25
2) Then 5^2x will be a bit greater than 5^4. 5^4 = 625
3) We know the answer is not exactly 4, rather it is slightly higher. 676 is the only answer choice that is even close to 625.
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