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a-5 ≤ 2.5
a ≤ 7.5.....1

5-a ≤ 2.5
2.5 ≤ a

2.5 ≤ a ≤ 7.5
Only 5 integral values: 3,4,5,6,7

IMO Option C
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|a−5|≤2.5

if a>=5, then a-5≤2.5, a≤7.5, a= 5,6, 7
if a<5, then a-5>= -2.5, a>= 2.5, a= 3, 4

So, a= 3,4, 5,6,7; So, I think C. :)
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|a−5|≤2.5

it means that 2.5≤a≤7.5

Thus a as in integer has to be 3,4,5,6,7

Push C
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Correct Answer C

How many integer values of a satisfy the inequality |a−5|≤2.5?
|a−5|≤2.5

squaring on both sides
(a-5)^2 ≤ (2.5)^2
(a-5)^2 - (2.5)^2 ≤0
(a-5 - 2.5)(a-5 + 2.5) ≤0
(a-7.5)(a-2.5) ≤0
On plotting on number line possible values between 2.5 and 7.5 are
3, 4, 5, 6, 7
Total =5
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Bunuel
How many integer values of a satisfy the inequality \(|a - 5| \leq 2.5\)?

A. 3
B. 4
C. 5
D. 6
E. 7




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After simplifying the equation:

2.5<= a <=7.5

Thus, integers satisfying the equation: 3/4/5/6/7

IMO option C is the answer.
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|a-5| <= 2.5
-2.5 <= a-5 <= 2.5
Adding 5 to all
2.5 <= a <= 7.5
So a can take 3, 4, 5, 6, 7 integer values.
So the answer will be C
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Firstly, considering positive relation we can get a-5<=2.5
Or a<=7.5
Secondly, considering negative relation ,
-a+5<=2.5
Or a>=2.5

A values lie in 2.5<=a<=7.5
So 3,4,5,6=4 values.
Ans: B

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