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Difficulty:
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Question Stats:
71% (01:18) correct
29%
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A company plans to assign identification numbers to its employees. Each number is to consist of four digits from 0 to 9, inclusive, except that the first digit cannot be 0. If any digit can be repeated any number of times in a particular code, how many different identification numbers are possible that are odd numbers?
(A) 2520
(B) 2268
(C) 3240
(D) 4500
(E) 9000
_________________
(A) 2520
(B) 2268
(C) 3240
(D) 4500
(E) 9000
_________________
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A four letter number is to be assigned. First digit cannot be zero.
Odd identification numbers =?
_ _ _ _
The first digit can be any number from 1 - 9 => 9 possibilities.
The central two digits can be any number from 0 - 9 => 10 possibilities for each digit
The last digit (unit digit) can be any one of {1,3,5,7,9} => 5 possibilities [for number to be odd]
Total possible odd identification numbers = 9 * 10 * 10 * 5 = 4500
So, correct answer is option D.
_________________
Odd identification numbers =?
_ _ _ _
The first digit can be any number from 1 - 9 => 9 possibilities.
The central two digits can be any number from 0 - 9 => 10 possibilities for each digit
The last digit (unit digit) can be any one of {1,3,5,7,9} => 5 possibilities [for number to be odd]
Total possible odd identification numbers = 9 * 10 * 10 * 5 = 4500
So, correct answer is option D.
_________________
Possible choice for various digits are
First =9 Excluding 0
Second=10
Third=10
Fourth=10
Answer=9*10*10*10=9000
Option E
First =9 Excluding 0
Second=10
Third=10
Fourth=10
Answer=9*10*10*10=9000
Option E
sumitkrocks
Any {1-9} * Any {0-9} * Any {0-9} * Any {1, 3, 5, 7, 9}
Outcomes = 9 * 10 * 10 * 5
sumitkrocks Odd numbers need to be made here so the unit digit will have 5 options {1, 3, 5, 7, 9}
So correct answer will be = 9*10*10*5 = 4500
Answer: Option D
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for the code the conditions given are
1. first digit cannot be 0
2. code has to be odd
3. repetition of digits is allowed
total possible codes will be
9*10*10*5 ; 4500
option D
1. first digit cannot be 0
2. code has to be odd
3. repetition of digits is allowed
total possible codes will be
9*10*10*5 ; 4500
option D
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