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Bunuel
In how many ways can 3 different prizes be distributed among 5 students when no student gets more than one prize?

(A) 60
(B) 100
(C) 120
(D) 124
(E) 125

Prices: 5 x 4 x 3 = 60

IMO A
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First prize can be given to a student in 5 ways. Since no student gets more than one prize, 2nd prize can be given in 4 ways and 3rd can be given in 3 ways

\(5*4*3=60\)

Answer is A­
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How many ways can you arrange ABCXX? 5!/2!=60
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