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Bunuel
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A positive integer when divided by 221 gives a remainder 43.

Let, the number be x
Dividend = x
Divisor = 221
Quotient = a (assume)
Remainder = 43
=> Dividend = Divisor * Quotient + Remainder
=> x = 221a + 43

What remainder will be obtained by dividing the same number by 17?

Remainder of x by 17
= Remainder of ( 221a + 43 ) by 17 = Remainder of 221a by 17 + Remainder of 43 by 17 = 0 + 9 = 9

So, Answer will be C
Hope it helps!

Playlist on Solved Problems on Remainders here

Watch the following video to MASTER Remainders

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