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Akshay_Naik
4 managers, 2 vice-presidents and 1 president have to be seated in a circle for a meeting such
that the two vice-presidents sit on either side of the president. In how many ways can they be
seated?

A. 120

B. 240

C. 36

D. 48

E. 72

Solution:

We have 4 managers, 2 vice-presidents and 1 president sitting at a circular table.

We are told that two vice-presidents sit on either side of the president. This means we have 2 scenarios there: \(VP_1 ,P, VP_2\) or \(VP_2, P, VP_1\)

Now let us assume VP, P, VP as a single entity because they will always be together. So we have 5 entities now including 4 managers.

Number of ways in which these 5 entities can sit around a round table \(= (5-1)!= 4!=24\). Because we know number of ways in which n people can sit in circle is \((n-1)!\)

These 24 arrangements can be done twice. Once in the case of \(VP_1 ,P, VP_2\) and other in the case of \(VP_2 ,P, VP_1\).

So total number of ways \(= 2\times 24 =48\)..

Hence the right answer is Option D.
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Akshay_Naik
4 managers, 2 vice-presidents and 1 president have to be seated in a circle for a meeting such
that the two vice-presidents sit on either side of the president. In how many ways can they be
seated?

A. 120

B. 240

C. 36

D. 48

E. 72

let the vice presidents be places between and considering them as a single unit

Therefore total number of people to be arranged in circular permutation = 5 in 4! ways

and the vice presidents can be arranged in 2! ways

Total number of arrangements = 4!*2! = 48
THerefore IMO D
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