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18 Nov 2021, 05:00
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Difficulty:
55%
(hard)
Question Stats:
66% (02:38) correct
34%
(02:39)
wrong
based on 230
sessions
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Positive integers x and y leave remainders 5 and 8 respectively when divided by 11. Which of the following is not a possible value of x + 2y?
A. 120
B. 196
C. 219
D. 351
E. 560
A. 120
B. 196
C. 219
D. 351
E. 560
18 Nov 2021, 05:36
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X=11Q+5
y=11z+8
x+2y= 11Q+22Z+21
11(Q+2Z)+11+10
So when divided by 11 , x+2y will leave 10 as a reminder .
196 will not leave 10 reminder when dived by 10.
Hence B.
y=11z+8
x+2y= 11Q+22Z+21
11(Q+2Z)+11+10
So when divided by 11 , x+2y will leave 10 as a reminder .
196 will not leave 10 reminder when dived by 10.
Hence B.
18 Nov 2021, 05:44
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x= 11k+5
y= 11m+8
x+2y will be of the form = 11*a+10
Only option (B) is not possible
y= 11m+8
x+2y will be of the form = 11*a+10
Only option (B) is not possible
Bunuel
