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28 Jan 2024, 15:24
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D
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If \((x + 3)^2 = y\), then in terms of y, \(x^2 + 6x + 17 =\)
A. y - 14
B. y - 8
C. y + 3
D. y + 8
E. y + 14
2024-01-29_02-18-48.png [ 14.63 KiB | Viewed 5042 times ]
A. y - 14
B. y - 8
C. y + 3
D. y + 8
E. y + 14
Attachment:
2024-01-29_02-18-48.png [ 14.63 KiB | Viewed 5042 times ]
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28 Jan 2024, 15:27
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guddo
Completing the square for \(x^2 + 6x + 17\), we get:
- \(x^2 + 6x + 9 + 8 =\)
\(=(x + 3)^2 + 8\)
Since \((x + 3)^2 = y\), we get:
- \((x + 3)^2 + 8 = y + 8\).
Answer: D.
Oppenheimer1945
Joined: 16 Jul 2019
Last visit: 23 Aug 2026
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Location: India
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GMAT Focus 1: 645 Q90 V76 DI80 
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Schools: INSEAD '26 (D) ISB '27 (D) IIMB '26 (A) IIMA '26 (A) HEC '26 (D) LBS '26 IESE '27 (D) Fuqua '27 (WL) Tepper '27 (WL)
GMAT Focus 1: 645 Q90 V76 DI80
Posts: 787
29 Jan 2024, 10:04
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x^2+6x+9=y
x^2+6x=y-9
x^2+6x+17=y-9+17=y+8
or x^2+6x+17=(x+3)^2+8
x^2+6x=y-9
x^2+6x+17=y-9+17=y+8
or x^2+6x+17=(x+3)^2+8
