Bunuel
In the sequence a1, a2, a3, …, an, an is determined for all values of n>2 by taking the average of all terms \(a_1\) through \(a_{n-1}\). If \(a_1=1\), what is the value of \(a_7\)?
(1) \(a_2=19\)
(2) \(a_3=10\)
Kudos for a correct solution. VERITAS PREP OFFICIAL SOLUTION:D. The key to nearly all sequence problems is to begin listing out the first few terms to arrive at a pattern. In this problem, beginning with statement 1, take a look at the first two terms:
1, 19
That means that the third term is the average of the first two terms, and is therefore 10. Which you should see matches statement 2 exactly (more on that in a second). If the first three terms, now (given only statement 1) are:
1, 19, 10
Then the sum of three terms is 30, and the average is again 10. So the fourth term is 10, and now you have:
1, 19, 10, 10
And you should see that the pattern will repeat indefinitely (if every new term is 10 and the original average is 10, the average won't change). So the answer must be 10, and statement 1 is sufficient.
Given statement 2, the same answers will hold. If the first term is 1 and the third is 10, then the second has to be 19. And at this point all the data is the same as it was for statement 1, so you're done - the answer again is 10, so statement 2 is also sufficient.