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hideyoshi
If x, y, b and t are all positive integers, \(x = \frac{y}{5} + 2\), and \(t = \frac{b}{7} + 4\), is \(b(t^{xy})\) an even number?

(1) 3.5t - 2 is even
(2) b/t is even

Source: - Prep4GMAT iOS app

we need to remember that:
e-e=e
o-o=e.
e-o=o
o-e=o

the question really asks whether t is even, since we know 100% that x and y are positive integers. thus, xy must be a positive integer, and the power will neither be negative nor fractional.

1. 3.5t-2=e.
only e-e=e. this only means that 3.5t is even. it can be even only when t is even.
sufficient.

2. b/t=e
b=7t-28
b/t=7-28/t.
this is even.
we know that even is only when o-o.
thus, it must be true that 28/t is odd.
therefore, we know for sure that t must be even.
(possible variations: 28/1; 28/2; 28/4 - we can see that only the last one actually satisfies the condition)
sufficient.

D
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hideyoshi
If x, y, b and t are all positive integers, \(x = \frac{y}{5} + 2\), and \(t = \frac{b}{7} + 4\), is \(b(t^{xy})\) an even number?

(1) 3.5t - 2 is even
(2) b/t is even

Source: - Prep4GMAT iOS app

we need to remember that:
e-e=e
o-o=e.
e-o=o
o-e=o

the question really asks whether t is even, since we know 100% that x and y are positive integers. thus, xy must be a positive integer, and the power will neither be negative nor fractional.

1. 3.5t-2=e.
only e-e=e. this only means that 3.5t is even. it can be even only when t is even.
sufficient.

2. b/t=e
b=7t-28
b/t=7-28/t.
this is even.
we know that even is only when o-o.
thus, it must be true that 28/t is odd.
therefore, we know for sure that t must be even.

(possible variations: 28/1; 28/2; 28/4 - we can see that only the last one actually satisfies the condition)
sufficient.

D

Hi,
Although you are correct with your solution
just two points on your solution ..
1) is \(b(t^{xy})\) an even number?
this means any of the b or t, if even, is sufficient... and just not only t
2) related to the above point
since b/t is even as per statement 2, this clearly means b is even and we dont require to see any further if t is even or not..
since b is even, the eq \(b(t^{xy})\) will be even
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