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Bunuel
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st 1: since a is even
expression is divisible by 2

Sufficient

St2: Since no clue on a
Insufficient

Ans: A
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Bunuel
If a and c are positive integers, is \(3^{11a} × a^{12c}\) divisible by 2?

(1) a = 4
(2) c = 15


hi,

I took the longer route of the cyclicity method. I want to know if that approach is also clear. Although I understand that the methods posted by other users are quite simple and easier.

since a=4, that means it will be 3^44 which will lead to a number ending with 1, since 3^4 will always end in number 1. further, 4^12(multiplied with any integer) will always result in an even number. Therefore, this statement would be sufficient.
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