A lottery game requires the entrant to select any 7-digit number. The

Question

A lottery game requires the entrant to select any 7-digit number. The contestant wins prize money based on the number of digits selected that match the winning 7-digit number. The grand prize, awarded to anyone who guesses all 7 digits correctly, is $2,200. Exactly how many correct numbers did Anna pick in the lottery game?

(1) Anna won $770

(2) If the contestant had picked one more correct number, she would have increased her winnings by $440.

(1) Anna won $770

(2) If the contestant had picked one more correct number, she would have increased her winnings by $440.

Divyadisha · Answer

Statement 1 told that Anna won 35% of the total amount. She could have picked 3 or 4. Not Sufficient.

Statement 2 told that if Anna had picked 1 more number she could have won 20% more of the amount. She could have picked 2 or 4. Not Sufficient.

Combining both statements, we get a unique number 4. Sufficient.

mikemcgarry · Answer

Dear AbdurRakib , I'm happy to help. :-)

I believe this question is poorly written. First of all, the amounts. 7 correct digits = 100% = $2200 We know that 50% = $1100 10% = $220 5% = $110 Thus, 5-6 correct digits = 55% = $1100 + $110 = $1210 3-4 correct digits = 35% = 30% + 5% = 3*($220) + $100 = $770 1-2 correct digits = 15% = 10% + 5% = $220 + $110 = $330 Statement #1 : Anna won $770 We know that Anna is in the 3-4 digit category, but she might have had 3 digits correct or four digits correct. Statement #2 : If the contestant had picked one more correct number, she would have increased her winnings by $440. The contestant could move from $330 to $770 or from $770 to $1210. She could have 2 or 4 correct. Combined : she must have 4 correct. Both statements are sufficient . OA = (C) What I find deeply problematic about this question is the wording " the contestant ." Since we are talking about a specific contestant, presumably we are talking about Anna, the only specific contestant named. This poor wording introduces unnecessary ambiguity into the problem. Here's a high quality question: Square and Triangle, Same Area Does all this make sense? Mike :-)

rohit8865 · Answer

770 is what % of 2200
770=A*2200/100 (let it be A %)
A=35%
35% falls under category for number 3-4
(1) number could be 3 or 4.Not suff.
(2) adding 1 to number2/ 4/6 will take her to next level 
where as adding 1 to number 1/3/5 will be 2/4/6 which is same level of %age winning
Combining both we get only adding 1 to number 4 will take her to next level of winning %age

Ans C

ronnieshee · Answer

mikemcgarry   AbdurRakib

Hello,

I am not being able to understand, that how could we infer about percentages in this problem? By reading the question, it feels that for getting 7 correct the amount is 2200. Nowhere is it mentioned that for getting different number of digits correct,the prize is different or unequal. For eg, for 2200 if 7 is correct, then for 1 correct it should be 2200/7.

now getting 770(35%) out of 2200 is not possible. Cause the values that one can get is (2200/7)*1 OR (2200/7)*2 OR (2200/7)*3 etc ....

Please correct if my understanding is wrong.

TPW · Answer

Same issue please someone throw some light  Bunuel

Posted from my mobile device

oekiz · Answer

I think it is related to the probability of having x number of matching digits.

For instance; 
Probability of matching 7 digits is the lowest percentage (p = 1/9*10^6) but 1-p = 100% of the price-winner,
Probability of matching one digit is the highest percentage but lowest percent of the price.

bumpbot · Answer

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