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Sub 505 (Easy)|   Algebra|               
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grantcke
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Bunuel chetan2u niks18 amanvermagmat

Is below approach valid?

Is ax=3-bx?

Question stem can be simplified to:

a = 3 - b provided x is not equal to zero.

Quote:
(1) x(a+b)=3
Either of terms on RHS can NOT be equal to zero.
Suff.


Quote:
(2) a=b=1.5 and x=1
We have values for all three unknown in this linear equation.
Clearly suff.
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adkikani
Bunuel chetan2u niks18 amanvermagmat

Is below approach valid?

Is ax=3-bx?

Question stem can be simplified to:

a = 3 - b provided x is not equal to zero.

Quote:
(1) x(a+b)=3
Either of terms on RHS can NOT be equal to zero.
Suff.


Quote:
(2) a=b=1.5 and x=1
We have values for all three unknown in this linear equation.
Clearly suff.


Hi adkikani

The highlighted part is incorrect

ax-3=bx, you cannot divide by x on both sides. You will have to rearrange the terms

So ax-3=bx can be written as ax-bx=3, hence x(a-b)=3
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Sooooooooo easy.

First simplify the given equation from the question.
You will find statement one.
Therefore st1 sufficient
St.2 just substitute. Sufficient

D

Sent from my XT1562 using GMAT Club Forum mobile app
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