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Omar7235
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Omar7235
If x and y are positive integers, is x a multiple of y?

(1) 2x is a multiple of y.
(2) 2(y^2) + y = 2x

Similar questions to practice:
https://gmatclub.com/forum/if-x-and-y-a ... 20420.html
https://gmatclub.com/forum/if-x-and-y-a ... 89048.html
https://gmatclub.com/forum/if-x-and-y-a ... 10085.html
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Bunuel

(2) 2(y^2) + y = 2x --> divide by 2y: \(y + \frac{1}{2} = \frac{x}{y}\). Thus \(\frac{x}{y}=y+ \frac{1}{2}=integer+noninteger=noninteger\). Sufficient.

Answer: B.


Dear Bunuel,

You have divided by 2y because it is mentioned that y is positive integer so we are certain that there is possibility to equal Zero.

Am I right?

Thanks
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Bunuel

(2) 2(y^2) + y = 2x --> divide by 2y: \(y + \frac{1}{2} = \frac{x}{y}\). Thus \(\frac{x}{y}=y+ \frac{1}{2}=integer+noninteger=noninteger\). Sufficient.

Answer: B.


Dear Bunuel,

You have divided by 2y because it is mentioned that y is positive integer so we are certain that there is possibility to equal Zero.

Am I right?

Thanks
_______________
Yes.
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Omar7235
If x and y are positive integers, is x a multiple of y?

(1) 2x is a multiple of y.
(2) \(2y^2 + y = 2x\)

Dear Omar7235, Could you please quote the source of the question? Thank you. :-D
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Omar7235
If x and y are positive integers, is x a multiple of y?

(1) 2x is a multiple of y.
(2) 2(y^2) + y = 2x

For Statement 2:

Let's say y=2
LHS= 10
x=5

Not a Multiple.

Let's say y=3
LHS=21

x won't be an integer.

Hence Sufficient.
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Omar7235
If x and y are positive integers, is x a multiple of y?

(1) 2x is a multiple of y.
(2) 2(y^2) + y = 2x

For Statement 2:

Let's say y=2
LHS= 10
x=5

Not a Multiple.

Let's say y=3
LHS=21

x won't be an integer.

Hence Sufficient.
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