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From the question stem
\(\frac{1}{x}-\frac{1}{y}<0\) -> \(\frac{y-x}{xy}<0\)?
since \(x>y\) -> \((y-x)<0\) then \(\frac{negative}{xy}<0\)

Two cases

\(\frac{negative}{positive}<0\)
\(\frac{negative}{negative}\) becomes positive


Simplified question stem is xy>0 (or simpler question stem does x & y have same signs?)

a) x is negative,
y must also be negative as x>y so sufficient

b) y is negative
since x>y
x can be positive, then NO
x can be negative then Yes
Not sufficient.

Answer A
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