RaghavKhanna
Bunuel Sir,
Is there any better method to solve this question without plugging values?
I know the way I solved this problem might look weird but here's how I did it , I didn't use calculation at all ,I know we can answer this question if we find Tom is faster than Foster or vice versa , if I find it I can answer the question , in order to find the work rate and since they are using a comparison , the comparison needs to be on the same ground , I will explain how I solved this problem logically (yes in DS you can save time by not calculating)
so let's start with the first statement:
Quote:
Tom takes 4 hours more than Matt to produce twice the number of pots.
in just two examples i will show how with this statement can make Tom faster than Matt and vice versa
let's say that Matt produces X amount of pots in 1 hour , so Tom produces 2X in five hours , the work rate of matt is X pot/hour , and Tom is Xpots/2.5 hours , matt is faster than Tom , so under these conditions , Matt is faster.
Another case , Matt produces X amount of pots in 20 hours , so Tom produces 2X in 25 hours , the work rate of Matt is 0.2X/hour , and Tom rate is 0.25X/hour, now Tom in this case is faster
1 insufficient.
for the statement 2: this one will always give us one answer (sufficient)
for example Tom takes 2* T to produce 3* X (T is time for matt to produce X matt) , so Tom has a work rate of 3*X/2*T it means 1.5 X pots / T hours , whereas matt takes X pot/ T hours , so here Tom is always faster
B is correct.
understanding this concept makes you answer this question in 50 seconds.