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03 Jan 2021, 15:57
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65%
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Question Stats:
60% (02:18) correct
40%
(02:45)
wrong
based on 139
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In how many ways can 141 be divided into two parts such that one part is divisible by 5 and the remaining part is divisible by 9?
A. 1
B. 2
C. 3
D. 4
E. 5
A. 1
B. 2
C. 3
D. 4
E. 5
03 Jan 2021, 16:07
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There are only 3 ways in which first number is divisible by 5 and second part is divisble by 9
(105,36), (60,81) and (15,126)
Ans C
(105,36), (60,81) and (15,126)
Ans C
03 Jan 2021, 16:08
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Since 5 and 9 are co prime numbers, their LCM is 5 x 9 = 45. Since 141 can be divided by 45 3 times (45 x 3 = 135, which is less than 141), so 141 can be split into two such numbers in 3 ways.
The numbers are -
15 + 127 = 141
60 + 81 = 141
105 + 36 = 141
Posted from my mobile device
The numbers are -
15 + 127 = 141
60 + 81 = 141
105 + 36 = 141
Posted from my mobile device
