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If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

(A) $280 (B) $800 (C) $892 (D) $1,108 (E) $1,200

y = 2000 - x


.1x - .08(2000-x) = 56

.-160+.18x = 56

x = 1200 and y = 800

my answer is B
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If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200

2% = 56
1% = 28
10% = 280
100% 2800

0.10x - 0.8y = 56
X + y = 2000
X = 2000 - Y

0.10 (2000 – Y ) – 0.8Y = 56

200 – 0.10Y – 0.8Y = 56

-0.18Y = -144

Y = 800
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2 equations with 2 unknowns

10x / 100 - 8y / 100 = 56

and

x + y = 2000

Solving these 2 equations, x = 1200 and y = 800

Answer B.
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annual income = principal + interest

for x @ 10% x + 10/100 * x = 1.1 x
for y @ 8% y + 8/100 * y = 1.08y

x+y = 2000

1.1x - 1.08y = 56
1.1 (2000-y) - 1.08y = 56
2200-1.1y-1.08y = 56
2.08y = 2144

y= 2144/2.18 = 983.46

so the question stem must say the annual interest difference rather than annual income difference.
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tonebeeze
If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

a. $280
b. $800
c. $892
d. $1108
e. $1200

We are given that x = the number of dollars invested at 10% and y = the number of dollars invested at 8%. We are also given that the total amount invested is $2000, and thus we have x + y = 2000 or x = 2000 - y. Finally, we are given that the annual income from the 10% investment exceeds the annual income from the 8% investment by $56, so we can create the following equation to determine the value of y:

0.10x = 0.08y + 56

0.10(2000 - y) = 0.08y + 56

200 - 0.10y = 0.08y + 56

144 = 0.18y

14400 = 18y

y = 14400/18 = 800

Answer: B
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everyone above has mentioned the conventional method. Which almost takes 2 mins. if anyone could suggest an approach for easy POE. Bunuel chetan2u sayantanc2k
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Agreed. Can someone please explain this? Thanks

amit2k9
annual income = principal + interest

for x @ 10% x + 10/100 * x = 1.1 x
for y @ 8% y + 8/100 * y = 1.08y

x+y = 2000

1.1x - 1.08y = 56
1.1 (2000-y) - 1.08y = 56
2200-1.1y-1.08y = 56
2.08y = 2144

y= 2144/2.18 = 983.46

so the question stem must say the annual interest difference rather than annual income difference.
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Hi Pankaj0901,

The principal amount invested in an account is NOT income, so the short answer is that amit2k9's interpretation of the prompt is not correct. The income in this case is any 'new' money that is placed into the account from the interest that is generated on that account. If you wanted to approach this Algebraically, then you could create the following 2 equations (and then solve via Substitution or Combination):

X + Y = 2000
.1X - .08Y = 56

As an alternative, you would likely find TESTing THE ANSWERS to be a lot faster.

GMAT assassins aren't born, they're made,
Rich
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Thank you EMPOWERgmatRichC
Your first statement clarifies my doubt - The principal amount invested in an account is NOT income.

EMPOWERgmatRichC
Hi Pankaj0901,

The principal amount invested in an account is NOT income, so the short answer is that amit2k9's interpretation of the prompt is not correct. The income in this case is any 'new' money that is placed into the account from the interest that is generated on that account. If you wanted to approach this Algebraically, then you could create the following 2 equations (and then solve via Substitution or Combination):

X + Y = 2000
.1X - .08Y = 56

As an alternative, you would likely find TESTing THE ANSWERS to be a lot faster.

GMAT assassins aren't born, they're made,
Rich
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y = 2000 - x


.1x - .08(2000-x) = 56

.-160+.18x = 56

x = 1200 and y = 800

Posted from my mobile device
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tonebeeze
If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

a. $280
b. $800
c. $892
d. $1108
e. $1200

We are given that x = the number of dollars invested at 10% and y = the number of dollars invested at 8%. We are also given that the total amount invested is $2000, and thus we have x + y = 2000 or x = 2000 - y. Finally, we are given that the annual income from the 10% investment exceeds the annual income from the 8% investment by $56, so we can create the following equation to determine the value of y:

0.10x = 0.08y + 56

0.10(2000 - y) = 0.08y + 56

200 - 0.10y = 0.08y + 56

144 = 0.18y

14400 = 18y

y = 14400/18 = 800

Answer: B



Why it is 0.10x = 0.08y + 56
and not
1.1x-1.08y=56 ??
kindly Help
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Nsp10
JeffTargetTestPrep
tonebeeze
If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

a. $280
b. $800
c. $892
d. $1108
e. $1200

We are given that x = the number of dollars invested at 10% and y = the number of dollars invested at 8%. We are also given that the total amount invested is $2000, and thus we have x + y = 2000 or x = 2000 - y. Finally, we are given that the annual income from the 10% investment exceeds the annual income from the 8% investment by $56, so we can create the following equation to determine the value of y:

0.10x = 0.08y + 56

0.10(2000 - y) = 0.08y + 56

200 - 0.10y = 0.08y + 56

144 = 0.18y

14400 = 18y

y = 14400/18 = 800

Answer: B



Why it is 0.10x = 0.08y + 56
and not
1.1x-1.08y=56 ??
kindly Help


Hi Nsp10,

The principal amount invested in an account is NOT income, so that interpretation of the prompt is not correct. The income in this case is any 'new' money that is placed into the account from the INTEREST that is generated on that account. If you wanted to approach this Algebraically, then you could create the following 2 equations (and then solve via Substitution or Combination):

X + Y = 2000
.1X - .08Y = 56

As an alternative, you would likely find TESTing THE ANSWERS to be a lot faster.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at: [email protected]
www.empowergmat.com
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Thank you EMPOWERgmatRichC.
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Please do not use algebra to solve this. This will just make you wate your time. Try using option elimination.

One such method is described below.

Lete me assume these are equally distributed , 100 $ each. The the interests would be 80 $ and 100 $ respectively, for x and y and x is 20 more than y.
Now the target difference is 56 $, which means that x > 1000 or y < 1000 for sure, so options D and E are eliminated. Also we can guess that A is too small a number considering 50/50 split gave us 20$ already so A is gone too.

Now just substituting the easier of the two remaining options which is 800 (B), we see that the diff is 120- 64 =56.

TADA !!
So B is the solution.

This way you can solve in less than 2 minutes.

Always remember, as Charles says :

Every question in GMAT quant can be solved in 2 mins.
It is not math, it is quantitative reasoning
Have I seen every possible solution path ?
Have I found the best possible solution path ?
Have I invested enough time in the begining to find the best possibe solution path ?
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lan583
If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?

(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200


Given

2000 = x + y..............equ 1
56 = 0.1x - 0.08y.............equ 2

multipy equ 1 with 0.1, you get 200 = 0.1x + 0.1y

subtract equ 1 by 2, you get

0.1x + 0.1y = 200
0.1x - 0.08y = 56
________________
0.18y = 144

y = 144/0.18 = 144*100/18 = 8*100 = 800
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