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Attachment:
Cube - Q.jpg
Cube - Q.jpg [ 21.46 KiB | Viewed 32094 times ]
The figure above is a cube. What is the measure of angle BEG (not shown)?
A. 30°
B. 45°
C. 60°
D. 75°
E. 90°

Hi everyone,
I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance
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Bunuel
htbreme

Hi everyone,
I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance

Added a question about this issue for a better understating.

Attachment:
Cube.jpg
The figure above is a cube. What is the measure of angle BEG (not shown)?
A. 30°
B. 45°
C. 60°
D. 75°
E. 90°

Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.

Answer: C.

Hope it helps.

Why isn't it 90? Since two diagonals bisect two 90 degree angles would the x angle equal to 90? I understand your explanation, but would like to understand why my thinking is wrong? Thank you.
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htbreme

Hi everyone,
I wanted to make you a quick and apparently easy question that it's giving me a hard time:

What is the angle formed by the diagonals of to perpendicular faces of a cube?

I know the answer but I can't visualize why that's the answer

Source: local GMAT course

Thanks in advance

Added a question about this issue for a better understating.

Attachment:
The attachment Cube.jpg is no longer available
The figure above is a cube. What is the measure of angle BEG (not shown)?
A. 30°
B. 45°
C. 60°
D. 75°
E. 90°

Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.

Answer: C.

Hope it helps.

Why isn't it 90? Since two diagonals bisect two 90 degree angles would the x angle equal to 90? I understand your explanation, but would like to understand why my thinking is wrong? Thank you.

It would be correct for 2-D geometry, meaning the angle between two diagonals below is indeed 90 degrees:
Attachment:
Squares.png
Squares.png [ 2.5 KiB | Viewed 30938 times ]
But in 3-D geometry 2 faces are already 90 degrees to each other thus their diagonals would not form 90 degrees any more.

Hope it's clear.
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I don't understand this question. Where is there a triangle/an angle for BEG?

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I don't understand this question. Where is there a triangle/an angle for BEG?

Posted from my mobile device



Note that triangle BEG is equilateral: it's made by the diagonals of the adjacent faces of the given cube (and as faces of a cube are squares its diagonals are equal). Thus angle BEG=60 degrees.
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Attachment:
The attachment Cube.jpg is no longer available
The figure above is a cube. What is the measure of angle BEG (not shown)?
A. 30°
B. 45°
C. 60°
D. 75°
E. 90°


Please find the solution as attached
Attachments

File comment: www.GMATinsight.com
Answer 3.jpg
Answer 3.jpg [ 58.96 KiB | Viewed 24487 times ]

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Baten80
Attachment:
Cube.jpg
The figure above is a cube. What is the measure of angle BEG (not shown)?
A. 30°
B. 45°
C. 60°
D. 75°
E. 90°

Since our given figure is a cube, we must recall that a cube is made up of 6 squares, which of course have all equal sides. We need to determine the measure of angle BEG. Let’s draw that angle in a diagram:



From our diagram we can see that we can actually create a triangle using angle BEG with sides BE, EG, and GB. Notice that each side is the diagonal of a square face of the cube and thus is equal in length. Therefore, we know that triangle BEG is an equilateral triangle and furthermore that angle BEG is 60 degrees.

Answer: C
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Easier to visualize if you consider GDB angle so that the telescoped perspective doesn't throw you off.

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