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555-605 (Medium)|   Multiples and Factors|                  
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Bunuel
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We can test examples as below:

A) 15+5 is divisible by 10
B) -10 is divisble by 10
C) 2*5 is divisible by 10
D) (19+20+21) is divisible by 10
E) All odd integers are not divisible by 10

Answer E.
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(A) The sum of two odd integers
ODD+ODD= EVEN
e.g. 5+5=10
(B) An integer less than 10
Zero is a multiple of every integer.

(C) The product of two primes
2*5= 10

(D) The sum of three consecutive integers
a, a+1, a+2
a+a+1+a+2= 3(a+1)

If a= -1, then the consecutive integers would be -1,0,1
The answer would be zero which is a multiple of every integer.

(E) An odd integer
Correct answer. An odd integer can never be divisible by 10 as all the multiples of 10 end in 0 and thus will leave a remainder.
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Just one tip: 0 is an integer!
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Even though I chose the correct answer, initially it was not so clear for me to check the answer D.
(D) The sum of three consecutive integers

My approach as follows, we need to find the multiple of 10;
Hence, (First + Last)/2 = Aver, in our case Aver will be 10
(x + x + 2)/2 = 10
2x + 2 = 20
x = 9

The sum of three consecutive integers: x + x +1 x + 2 = 9, 10, 11 = 30/10 = Int.
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The big takeaway from this one is to always look at all of the answers first before diving into test cases. E is such an obvious answer, but the test writers hide it in the last option as a trap to get you to waste time.
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In this type of questions I would always start with E. To be divisible by 10 it must be divisible by 2 and 5. Since Odd integers are never divisible by 2 E is right away the correct answer. No need to check the other answers
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