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Updated on: 31 Jan 2013, 04:49
Originally posted by antoxavier on 30 Jan 2013, 23:30.
Last edited by Bunuel on 31 Jan 2013, 04:49, edited 2 times in total.
Last edited by Bunuel on 31 Jan 2013, 04:49, edited 2 times in total.
Renamed the topic and edited the question.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
68% (01:13) correct
32%
(01:15)
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Find the probability that a leap year selected at random will have 53 Sundays
A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
A. 6/7
B. 5/7
C. 4/7
D. 3/7
E. 2/7
31 Jan 2013, 04:48
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antoxavier
There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.
These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case.
The probability of that is 2/7.
Answer: E.
Hope it's clear.
General Discussion
22 Mar 2017, 02:27
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Any given year will always have 52 complete weeks. So 52 Sundays will always be there in any year.
A leap year has 366 days.
52 weeks = 52*7=364 days
So we have 2 extra days apart from 52 weeks.
These 2 days can be (Saturday, Sunday), (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday,Thursday), (Thursday, Friday), (Friday, Saturday).
For the year to have 53 Sundays, the 2 days must be either (Saturday, Sunday) or (Sunday, Monday)
Favourable cases = 2
Total possible cases = 7
Propability = \(\frac{Favourable}{Total}\)= \(\frac{2}{7}\)
Answer E
A leap year has 366 days.
52 weeks = 52*7=364 days
So we have 2 extra days apart from 52 weeks.
These 2 days can be (Saturday, Sunday), (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday,Thursday), (Thursday, Friday), (Friday, Saturday).
For the year to have 53 Sundays, the 2 days must be either (Saturday, Sunday) or (Sunday, Monday)
Favourable cases = 2
Total possible cases = 7
Propability = \(\frac{Favourable}{Total}\)= \(\frac{2}{7}\)
Answer E
