stonecold wrote:
Hey
chetan2uI am having trouble understanding this Question.
I have seen all the solutions above,but none of them is making sense to me.
You mind solving this one.
Here is what i did
Given => 21 white and 92 red tulips
So to make identical bouquets we can make the arrangement as follows =>
1 each for 21 bouquets in which
2 each for 10 bouquets and and one in the last one.
And we can continue this way to make infinite arrangements.
I understand the use the word "identical" but if w give 2 each => we can make 10 identical bouquets and one bouquets with leftover flowers right ?
What i am missing here?
It feels like a pretty difficult Question to me.
Regards
Stone Cold
Hi,
What the Q means is that each bouquet is identical so each should have same number of white,w , and same number of red, say r..
Now w has to be a factor of 21 , since if you take 2 the last bouquet will have only 1, thus all will not be identical.
Only w as 1, 3, 7 or 21 will fit in..
Similarly r should be a factor of 91, so 1, 7,13 or 91..
Example each has7,7..., so 91/7=13 bouquets of 7 red, OR each has 13, so 7 bouquets of 7 each...
Now the MAIN point comes out is both white and red have to be divided in same number of bouquets ...
So only identical are 1and 7..
So two ways bouquets can be identical
1) All 21 and 91 together as 1 bouquet
2) We distribute 21 in 7 bouquets and 91 red too in 7 bouquets
So we will have 7 identical bouquets, each bouquet having 21/7=3 white and 91/7=13 red tulips..
So ans 7