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What is the median number of employees assigned per project [#permalink]

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01 Jul 2009, 11:41

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C

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E

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What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

None of the statements are giving any concrete information.

Anything that would give us exact number of employees in the central values would help. ie, number of employees in the projects having central values in the range.

What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

Stat 1 25 percent of the projects at Company Z have 4 or more employees assigned to each project. No info on rest of the projects

stat 2 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project. No info on rest of the projects

combining stat 1 and stat 2.

Rest of the 40 percent of the projects may have 3 employees but as we don't know the exact number of employees, we can't find the median number of employees.

I assume the answer may be E..
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Am I missing something here...I think the answer should be C.

If 75% of the projects have less than 4 and 65% have greater than 2 => the median has to be whatever is the number of employees for the 50% of the projects. And in this case the only number that is >2 and <4 is 3.

So the median is 3 employees per project, since we cannot 3.5 persons (non integers) on a project...

Also, we dont need the number of projects here, because we are not asked the mean/average. We are asked to find the median...

Am I missing something here...I think the answer should be C.

If 75% of the projects have less than 4 and 65% have greater than 2 => the median has to be whatever is the number of employees for the 50% of the projects. And in this case the only number that is >2 and <4 is 3.

So the median is 3 employees per project, since we cannot 3.5 persons (non integers) on a project...

Also, we dont need the number of projects here, because we are not asked the mean/average. We are asked to find the median...

What is the OA???

statements are not saying more than 4, less than 2

What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

I am rephrasing the given stmts to below -

(1) Doesnt stmt 1 imply that 75% have < 4 employees...? (2) Doesnt stmt 2 imply that 65% have > 2 employees...?

Now going by the two stmtys together, can't we say that median (which is what 50% of projects have) is 3

Stat 1 says - 25 percent of the projects at Company Z have 4 or more employees assigned to each project.

You say - Doesnt stmt 1 imply that 75% have < 4 employees...?

Note the word 4 or more. doesn't mean less than 4. It could be less than 5 also.

sdrandom1 wrote:

Yes rashimnet, I understand that....

What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

I am rephrasing the given stmts to below -

(1) Doesnt stmt 1 imply that 75% have < 4 employees...? (2) Doesnt stmt 2 imply that 65% have > 2 employees...?

Now going by the two stmtys together, can't we say that median (which is what 50% of projects have) is 3

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As soon as you infer that 75% have <4 employees you are including the (b)stmnts 35% employees in that 75% also.This 35% have 2 or fewer employees which contradicts your rephrased stmnt.

What is the median number of employees assigned per project for the projects at Company Z? (1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project. (2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.

I am rephrasing the given stmts to below -

(1) Doesnt stmt 1 imply that 75% have < 4 employees...? (2) Doesnt stmt 2 imply that 65% have > 2 employees...?

Now going by the two stmtys together, can't we say that median (which is what 50% of projects have) is 3

Yes, it's clearly C. The wording you use above (when you say that the median 'is what 50% of projects have') is not technically correct, however. To find the median, you're looking for the 'middle number', so I think what you meant was that you were looking for the value in the 50th percentile. Here, of course, we have, using both statements:

25% have 4 or more employees 40% have exactly 3 employees 35% have 2 or fewer employees

So the number in the middle must be 3 -- certainly 50% of the values are 3 or greater, and 50% are 3 or less, so 3 must be the median.
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