sdrandom1 wrote:

Yes rashimnet, I understand that....

What is the median number of employees assigned per project for the projects at

Company Z?

(1) 25 percent of the projects at Company Z have 4 or more employees assigned to

each project.

(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to

each project.

I am rephrasing the given stmts to below -

(1) Doesnt stmt 1 imply that 75% have < 4 employees...?

(2) Doesnt stmt 2 imply that 65% have > 2 employees...?

Now going by the two stmtys together, can't we say that median (which is what 50% of projects have) is 3

Yes, it's clearly C. The wording you use above (when you say that the median 'is what 50% of projects have') is not technically correct, however. To find the median, you're looking for the 'middle number', so I think what you meant was that you were looking for the value in the 50th percentile. Here, of course, we have, using both statements:

25% have 4 or more employees

40% have exactly 3 employees

35% have 2 or fewer employees

So the number in the middle must be 3 -- certainly 50% of the values are 3 or greater, and 50% are 3 or less, so 3 must be the median.

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