Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost.
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application...
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
What is the units digit of 314673^2 × 976452^3 × (32168^5 + 865^2)^479?
A. 0
B. 1
C. 2
D. 5
E. 8
Show more
Hi... Relook at the Q and choices, 0 can never be the units digit here..
For ANSWER let's see only the units digit.. \(3^2*2^3*(8^5+5^2)^{479}\) ... This means \(9*8*(8+5)^{480-1}\) 480 is div by 4 so units digit of base will be same as that of 4-1 or 3.. So 72*13^3.....2*3^3=2*7=14.. Units digit is 4
What is the units digit of 314673^2 × 976452^3 × (32168^5 + 865^2)^479?
A. 0
B. 1
C. 2
D. 5
E. 8
Hi... Relook at the Q and choices, 0 can never be the units digit here..
For ANSWER let's see only the units digit.. \(3^2*2^3*(8^5+5^2)^{479}\) ... This means \(9*8*(8+5)^{480-1}\) 480 is div by 4 so units digit of base will be same as that of 4-1 or 3.. So 72*13^3.....2*3^3=2*7=14.. Units digit is 4
What is the units digit of 31467^32 × 97645^23 × (32168^5 + 8652)^479?
A. 0
B. 1
C. 2
D. 5
E. 8
Show more
For ANSWER let's see only the units digit.. \(7^{32}*5^{23}*(8^5+2)^{479}\) ... This means \(7^4*5*(8^1+2)^{480-1}\)...... after every 4th power, the units digit repeat for units digit 0, 1, 5 and 6... it remains the same for every positive integer power for 2,3,7,8 it repeats after every 4th.. so 2^401 will be same as 2^(4*50+1) or 2^1 4 and 9 repeat after every second.. so \(7^4*5\) will be 5 as ODD *5 will have units digit 5 but \((8^1+2)^{479} = 10^{479}\) will always have 0 as units digit.. so overall also it will be 0
What is the units digit of 31467^32 × 97645^23 × (32168^5 + 8652)^479?
A. 0
B. 1
C. 2
D. 5
E. 8
For ANSWER let's see only the units digit.. \(7^{32}*5^{23}*(8^5+2)^{479}\) ... This means \(7^4*5*(8^1+2)^{480-1}\)...... after every 4th power, the units digit repeat for units digit 0, 1, 5 and 6... it remains the same for every positive integer power for 2,3,7,8 it repeats after every 4th.. so 2^401 will be same as 2^(4*50+1) or 2^1 4 and 9 repeat after every second.. so \(7^4*5\) will be 5 as ODD *5 will have units digit 5 but \((8^1+2)^{479} = 10^{479}\) will always have 0 as units digit.. so overall also it will be 0
What is the units digit of 31467^32 × 97645^23 × (32168^5 + 8652)^479?
A. 0
B. 1
C. 2
D. 5
E. 8
For ANSWER let's see only the units digit.. \(7^{32}*5^{23}*(8^5+2)^{479}\) ... This means \(7^4*5*(8^1+2)^{480-1}\)...... after every 4th power, the units digit repeat for units digit 0, 1, 5 and 6... it remains the same for every positive integer power for 2,3,7,8 it repeats after every 4th.. so 2^401 will be same as 2^(4*50+1) or 2^1 4 and 9 repeat after every second.. so \(7^4*5\) will be 5 as ODD *5 will have units digit 5 but \((8^1+2)^{479} = 10^{479}\) will always have 0 as units digit.. so overall also it will be 0
A
Show more
chetan2u , I'm not clear about why you wrote this part: \((8^1+2)^{480-1}\). (480/4) is evenly divisible, maybe the (-1) is a negative remainder (and I will never understand negative remainders fully) but that doesn't seem to explain the exponent manipulation, either. . .
Was it to show remainder in case \((8^1+2)\) summed to something other than zero? If that is the reason, I still don't follow.
You can't distribute the exponent, so cyclicity of four for addends 8 and 2 can't be the reason.
And cyclicity per se doesn't seem to be the reason: 2, 3, 7, and 8 have cyclicity of four (where 480 is divisible by 4) - but 0, 1, 4, 5, 6, and 9 do not have cyclicity of four. That 8 might have had units digit 2, e.g. Then units digit is 4, and I can't see how \(4^{480-1}\) helps.
The (-1) part isn't clear, either. I suppose I know that, in the number whose cyclicity of powers is four, I can take the \(n^4\) term and "move backwards" by one power in the cycle to get the units digit, but 479/4 leaves remainder 3, which is the same thing as "moving one place backward" in the cycle. It seems harder to see, from a divisibility perspective, that (-1) power in cycle = (+3) power in cycle.
I looked only at \(8^5\), where 5/4 = remainder 1, units digit of first term is same as \(8^1\) = 8. Last digit of addend in parentheses is 2. (8 + 2) = 0.
And as you point out, zero to any power (except zero) is 0. So I just wrote (first expression) * 0.
Sorry if this confusion arises because I am missing something obvious. I suspect what you wrote is important for problems different from this one. Please explain?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.