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Simple and easy approach.

Statement 1
\(y-1 = x\)
\(y = x+1\)
\(xy = x (x+1)\)
\(xy = x^2 +x\)
INSUFFICIENT

Statement 2
\(x^2 + x - 6 = 0\)
\(x^2 + 3x - 2x - 6 = 0\)
\(x(x + 3) - 2(x + 3)\)
\((x + 3)(x - 2) = 0\)
\(x = -3 or x = 2\)
INSUFFICIENT

BOTH Statement 1 and 2

We know,
\(x^2 + x - 6 = 0\)
and
\(xy = x^2 + x\)
Therefore,
\(xy - 6 = 0\)
\(xy = 6\)
SUFFICIENT
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The answer is C.

Statement 1 : Does not give us any value about x or y. Insufficient.

Statement 2 : On solving this we get 2 values for x, x= -3,2. But we don't know anything about 'y' to determine the value of 'xy'.

On combining bothe statements we get x,y = -3,-2 or 2,3. For both these pairs the value of xy = 6. So, together they are sufficient.

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