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GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
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RaghavSingla
Joined: 27 Jan 2013
Last visit: 10 Jun 2020
Posts: 84
Own Kudos:
Given Kudos: 41
Location: India
Schools: EDHEC Sept Intake"17 (A)
GMAT 1: 700 Q49 V35
GPA: 3.7
01 Aug 2016, 07:02
Kudos
Bookmarks
1+2 =7 -----> (1^2 + 2^2) + (1+2) -1
3+4 = 31 -----> (3^2 + 4^2) + (3+4) -1
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9+10 = 199 ----> (9^2 + 10^2) + (9+10) -1
3+4 = 31 -----> (3^2 + 4^2) + (3+4) -1
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9+10 = 199 ----> (9^2 + 10^2) + (9+10) -1
09 Aug 2016, 02:38
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199
(a*b*2)+(a+b)=c
9*10*2=180
180+9+10=199
1+2=7,
1+2=3, 7-3=4,
4=4x1 (1) / 3+4=31, 3+4=7,
31-7=24,
24=4x6 (6) / 5+6=71, 5+6=11,
71-11=60,
60=4x15, (15) / 7+8=127,
7+8=15,
127-15=112, 112=4x28 (28) ,
so, 6-1=5, 15-6=9, 28-15=13, (so 9-5=4, 13-9=4,) so, 9+10=19,
then if answer is x, so x-19=180 i.e(45x4), so, x=199
(a*b*2)+(a+b)=c
9*10*2=180
180+9+10=199
1+2=7,
1+2=3, 7-3=4,
4=4x1 (1) / 3+4=31, 3+4=7,
31-7=24,
24=4x6 (6) / 5+6=71, 5+6=11,
71-11=60,
60=4x15, (15) / 7+8=127,
7+8=15,
127-15=112, 112=4x28 (28) ,
so, 6-1=5, 15-6=9, 28-15=13, (so 9-5=4, 13-9=4,) so, 9+10=19,
then if answer is x, so x-19=180 i.e(45x4), so, x=199
