Quote:
Yes, the red parts in your solution are not correct at all. That is not how this inequality can be solved. I have highlighted above three different approaches you can use to solve it, the first one being the easiest. As for your question, I'm not sure I follow – where is the sign flipped, in which solution?
Thanks
Bunuel. I am actually able to solve using the 3 approaches above and get to the answer, but let me clarify my question. I am trying to clarify this, as I feel, there is a flaw in my understanding of fundamentals somewhere, which is why the below is not making sense to me.
if we have x+1<0, we can move 1 to the other side, and get x<-1. We dont flip signs, as we are not multiplying or divide.
Now coming to this question (Sorry I wrote the signs upside down in my last post by mistake), we have:
(x+1)≤0 = if I move 1 to the other side I should get x≤-1
(x−1)≤0 = similarly, here I get x≤1
Now, if I take those two values of X, I get x≤-1 or x≤1, but I do not get a compound equality, i.e. -1≤x≤1, which is the correct answer.
This means x≤-1 is obv. not correct and the sign is being flipped in the final answer. So why is this being flipped considering there is no multiplication or division by a negative involved?